PengKuan Em
2019-10-26 15:38:55 UTC
In Special Relativity relativity of simultaneity is the fact that 2 simulta=
neous events occurring in a stationary frame does not appear simultaneous i=
n a moving frame. For example, in Einstein's train thought experiment 2 sim=
ultaneous flashes of light on the platform do not appear simultaneous for t=
he observer in the train. But relativity of simultaneity has never been tes=
ted with real simultaneous events.
For testing relativity of simultaneity we need 2 synchronized clocks moving=
at high speed and we will read them in a stationary frame. Fortunately, we=
have at hand many GPS satellites which carry precision clocks and broadcas=
t their time, with which we can check relativity of simultaneity.=20
Suppose that 2 satellites are separated by the distance L in the same orbit=
. Their clocks are synchronized with one clock on Earth, that is, the event=
"time of the satellite 1 is t0" and the event "time of the satellite 2 is =
t0" occur simultaneously on Earth at the time te. In the frame of these 2 s=
atellites, due to relativity of simultaneity, these same events occur at ti=
me t1 on the satellite 1 and t2 on the satellite 2 and the difference of ti=
me is dt=3D t2- t1.
Suppose that we have n satellites equally spaced in the same orbit which is=
circular. The nth satellite is the last satellite and the (n+1)th satellit=
e is the first satellite, which complete the circle of the orbit.=20
Due to relativity of simultaneity, the difference of time is always dt from=
one satellite to the next and the difference of time between the ith satel=
lite and the first satellite equals (i-1)*dt. Then, the difference of time =
between the (n+1)th satellite and the first satellite equals n*dt. So, The =
time of the (n+1)th satellite is t1+n*dt.
We notice that the (n+1)th satellite is the first satellite but its time, t=
1+n*dt, is different from t1 the time of the first satellite. How can the =
time of a satellite is not the time of itself?=20
I explain this phenomenon in the article below.
PDF: https://pengkuanonphysics.blogspot.com/2019/10/testing-relativity-of-s=
imultaneity.html=20
Word: https://www.academia.edu/40736335/Testing_relativity_of_simultaneity_=
using_GPS_satellites =20
neous events occurring in a stationary frame does not appear simultaneous i=
n a moving frame. For example, in Einstein's train thought experiment 2 sim=
ultaneous flashes of light on the platform do not appear simultaneous for t=
he observer in the train. But relativity of simultaneity has never been tes=
ted with real simultaneous events.
For testing relativity of simultaneity we need 2 synchronized clocks moving=
at high speed and we will read them in a stationary frame. Fortunately, we=
have at hand many GPS satellites which carry precision clocks and broadcas=
t their time, with which we can check relativity of simultaneity.=20
Suppose that 2 satellites are separated by the distance L in the same orbit=
. Their clocks are synchronized with one clock on Earth, that is, the event=
"time of the satellite 1 is t0" and the event "time of the satellite 2 is =
t0" occur simultaneously on Earth at the time te. In the frame of these 2 s=
atellites, due to relativity of simultaneity, these same events occur at ti=
me t1 on the satellite 1 and t2 on the satellite 2 and the difference of ti=
me is dt=3D t2- t1.
Suppose that we have n satellites equally spaced in the same orbit which is=
circular. The nth satellite is the last satellite and the (n+1)th satellit=
e is the first satellite, which complete the circle of the orbit.=20
Due to relativity of simultaneity, the difference of time is always dt from=
one satellite to the next and the difference of time between the ith satel=
lite and the first satellite equals (i-1)*dt. Then, the difference of time =
between the (n+1)th satellite and the first satellite equals n*dt. So, The =
time of the (n+1)th satellite is t1+n*dt.
We notice that the (n+1)th satellite is the first satellite but its time, t=
1+n*dt, is different from t1 the time of the first satellite. How can the =
time of a satellite is not the time of itself?=20
I explain this phenomenon in the article below.
PDF: https://pengkuanonphysics.blogspot.com/2019/10/testing-relativity-of-s=
imultaneity.html=20
Word: https://www.academia.edu/40736335/Testing_relativity_of_simultaneity_=
using_GPS_satellites =20